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0=-0.005x^2+0.25x
We move all terms to the left:
0-(-0.005x^2+0.25x)=0
We add all the numbers together, and all the variables
-(-0.005x^2+0.25x)=0
We get rid of parentheses
0.005x^2-0.25x=0
a = 0.005; b = -0.25; c = 0;
Δ = b2-4ac
Δ = -0.252-4·0.005·0
Δ = 0.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.25)-\sqrt{0.0625}}{2*0.005}=\frac{0.25-\sqrt{0.0625}}{0.01} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.25)+\sqrt{0.0625}}{2*0.005}=\frac{0.25+\sqrt{0.0625}}{0.01} $
| (5x-3)=(147-x) | | 0.05(7t+6)=0.35(T-5)+2.5 | | 85;x-41=44 |